![]() In Verilog, if you want to create sequential logic use a clocked always block with nonblocking assignments. However, I would say that your code is combinational because it is not synchronized with clk signal and the ouput is changed according to a or b inputs and the output does not depend on previous state (such as q <= ~q). Also a rule of thumb is to use only blocking assignments in an block (e.g OUT = A & B).Ĭoncerning your verilog code, there is a CLK signal in your sensitivity list and non-blocking assignments are used (which are used only in sequential logic circuits). The sensitivity list is used at the beginning of an always procedure to infer combinational logic or sequential logic behavior in simulation. Which signals should trigger the elements inside the block to be updated. The star (*) represents the sensitivity list specifies ![]() which create problems when inferring sequential logic (of course latches are useful in some scenarios). A register is a simple, 1-bit memory device, either a. Register inference allows you to use sequential logic in your designs and keep your designs technology-independent. Trying to implement a typical stopwatch with Stop/Start and Lap/Reset buttons. Although many Verilog functional constructs (for example, for loops and multiple assignments to the same variable) appear sequential in. ![]() Regarding verilog code, one way to find out the combinational part from your module is to see the always block and its sensitivity (*) block is used to describe combinational logic and logic gates. New to Verilog, Basys3 board and Vivid 2021.2. In case that one of those conditions are not met, your circuit is sequential. Also a combinational circuit is time independent. You can find out if a circuit is combinational if the circuit does not depend on previous states. ![]()
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